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Tuesday, April 12, 2011

3. The Wirehouse Lumber Company will soon begin logging eight groves of trees in the same general area. Therefore, it must develop a system of dirt roads that makes each grove accessible from every other grove. The distance (in miles) between every pair of groves is as follows:


Distance between Pairs of Groves
Grove
1
2
3
4
5
6
7
8
1
-
1.3
2.1
0.9
0.7
1.8
2.0
1.5
2
1.3
-
0.9
1.8
1.2
2.6
2.3
1.1
3
2.1
0.9
-
2.6
1.7
2.5
1.9
1.0
4
0.9
1.8
2.6
-
0.7
1.6
1.5
0.9
5
0.7
1.2
1.7
0.7
-
0.9
1.1
0.8
6
1.8
2.6
2.5
1.6
0.9
-
0.6
1.0
7
2.0
2.3
1.9
1.5
1.1
0.6
-
0.5
8
1.5
1.1
1.0
0.9
0.8
1.0
0.5
-

Management now wants to determine between which pairs of groves the roads should be constructed to connect all groves with a minimum total length of road.

a. Describe how this problem fits the network description of a minimum spanning tree problem.

         This is because, we can find the possible distance of minimum spanning tree which connect the groves by using Kruskal's Algorithm.

b. Use the suitable algorithm to solve the problem.

                 n=8
                 n-1=7

Minimum spanning tree = 0.5+0.6+0.9+0.7+2.6+0.9+1.3
                                   = 7.5


5)What are a few types of applications of minimum spaning tree problems?
They are 5  types of applications of minimum spanning tree problems which are :-
a)      Transportation networks which it is used to minimize the total cost of providing the links (example : rail lines, road, etc)
b)      Telecommunication networks (computer networks, leased-line telephone networks, cable television method, etc)
c)       A network of pipelines to connect a number of locations.
d)      Design of a network of wiring on electrical equipment to minimize the total length of the wire (digital computer system)
e)      High-voltage electrical power transmission lines network.
faculty.ksu.edu.sa/72966/Documents/chap09.pdf

6) Use a Kruskal’s algorithm to find a minimum spanning tree for a network with the following nodes?



 Answer:

 
n = 7
(n-1) = 6
Weight: 4 + 1 + 2 + 4 + 1 +6 = 18